| Explanation | If the result is calculated from the birthday of a person, the `Day Fortune Co-ordinates' (G3, C3) are exactly the same as the `Origin of Day Fortune Co-ordinates' (UN3, ZN3). The daily fortune of a person starts to shift from the `Origin of Day Fortune Co-ordinates' at (UN3, ZN3) to the next `Day Fortune Co-ordinates' after the midnight at the location of the person. It always spins clockwisely on a daily base. The `Day Fortune Co-ordinates' oscillate in a loop of 60. `I[n]' is an integer function such that it takes the integral part of number `n' without rounding up the number. `G3=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If G3>10 then `G3' becomes `G3-10' and if G3<1 then `G3' becomes `G3+10'. Thus, the value range of `G3=(Mod 10)' is from 1 to 10. `C3=(Mod 12)' is a modulated function such that if C3>11 then `C3' becomes `C3-12' and if C3<0 then `C3' becomes `C3+12'. Thus, the value range of `C3=(Mod 12)' is from 0 to 11. In general, the `Day Fortune Co-ordinates' are expressed as (G3, C3), where `G3' and `C3' are integers. Since, `G3' always oscillates in a loop of 10 and `C3' always oscillates in a loop of 12, the `Day Fortune Co-ordinates' reckoning from 1st January of 1 can be determined mathematically by modulated functions of 10 and 12 with some constants as adjustments. That is `G3=(Mod 10)' and `C3=(Mod 12)'. For `G3' values, 1 is `A', 2 is `B', 3 is `C', 4 is `D', 5 is `E', 6 is `F', 7 is `G', 8 is `H', 9 is `I', 10 is `J'. So, (1, 0)=A0, (2, 1)=B1, (3, 2)=C2, and so on. If the number of days calculated by the formula is divisible by 10, then G3=10 and `G3' is `J' because `G3=10' stands for `J' in the `Fortune Code'. For `C3' values, 0 is `A', 1 is `B', 2 is `C', 3 is `D', 4 is `E', 5 is `F', 6 is `G', 7 is `H', 8 is `I', 9 is `J', 10 is `K', 11 is `L'. So, (1, 0)=1A, (2, 1)=2B, (3, 2)=3C, and so on. If it is divisible by 12, then C3=0 and `C3' is `A' because `C3=0' stands for `A' in the `Fortune Code'. For all in terms of alphabets, (1, 0)=AA, (2, 1)=BB, (3, 2)=CC, and so on. They are known as `Day Fortune Codes' or `Day Codes'. The `Day Fortune Code' is the `Fortune Code' of a day. Assume `y' be the number of years reckoning in Gregorian calendar of a date and `d' be the number of days reckoning from 1st January of that year in Gregorian calendar. The `Day Fortune' Formula for people in `y' B.C. is `G3=7+365(1-y)+I[(1-y)/4]-I[(1-y)/100]+I[(1-y)/400]-I[(1-y)/3225]+d (Mod 10) & C3=6+365(1-y)+I[(1-y)/4]-I[(1-y)/100]+I[(1-y)/400]-I[(1-y)/3225]+d (Mod 12)'. The `Day Fortune' Formula for people in `y' A.D. is `G3=5+365(y-1)+I[(y-1)/4]-I[(y-1)/100]+I[(y-1)/400]-I[(y-1)/3225]+d (Mod 10) & C3=2+365(y-1)+I[(y-1)/4]-I[(y-1)/100]+I[(y-1)/400]-I[(y-1)/3225]+d (Mod 12)'. [Remarks: The `Day Fortune Co-ordinates' of 1st January of A.D.1898, A.D.1921, A.D.1944, A.D.2001 & A.D.2024 are (1,0). ] |
| Example | Assume to find the `Day Fortune Co-ordinates' (G3, C3) of 6th October, A.D.1952. Then y=1952 and d=31+29+31+30+31+30+31+31+30+6. d=280. Apply the `Day Fortune' Formula for people in `y' A.D.. G3=5+365(y-1)+I[(y-1)/4]-I[(y-1)/100]+I[(y-1)/400]-I[(y-1)/3225]+d (Mod 10) & C3=2+365(y-1)+I[(y-1)/4]-I[(y-1)/100]+I[(y-1)/400]-I[(y-1)/3225]+d (Mod 12). G3=5+365(1952-1)+I[(1952-1)/4]-I[(1952-1)/100]+I[(1952-1)/400]-I[(1952-1)/3225]+280 (Mod 10). G3=5+712115+I[487.75]-I[19.51]+I[4.8775]-I[0.605]+280 (Mod 10). G3=5+712115+487-19+4-0+280 (Mod 10). G3=712872 (Mod 10). G3=2. C3=2+365(1952-1)+I[(1952-1)/4]-I[(1952-1)/100]+I[(1952-1)/400]-I[(1952-1)/3225]+280 (Mod 12). C3=2+712115+I[487.75]-I[19.51]+I[4.8775]-I[0.605]+280 (Mod 12). C3=2+712115+487-19+4-0+280 (Mod 12). C3=712869 (Mod 12). C3=9. Hence, the `Day Fortune Co-ordinates' (G3, C3) of 6th October of A.D.1952 is (2, 9). The `Day Code' of 6th October of A.D.1952 is `22', `B9', `2J', `BJ' or `EUT-YAU'. |
