gc7-e

Explanation

Since a pair of Second Fortune Co-ordinates represent fifty seconds, each pair of Tiny Fortune Co-ordinates represent 4 and one-sixth seconds (approximately 4.17 seconds). In general, the `Tiny Fortune Co-ordinates' are expressed as (G7,C7). `G7' is the Stem of Tiny Code and `C7' is the Root of Tiny Code. They are called `Tiny Stem' and `Tiny Root' of Fortune Code. The time interval of Stem and Root of Tiny Code is four and one-sixth seconds. As there are twelve values in `C7' and there are 50 seconds in a Second Code, a value of `C7' stands for four and one-sixth seconds (4.17 seconds). The value of `C7' shifts to the next after passing the time at 0 second, four and one-sixth seconds or a multiple of four and one-sixth seconds. The value of `C7' can be calculated directly from time `t' expressed in 24-hour system. But, for finding out the value of `G7', the `G6' value of `Second Fortune Co-ordinates' (G6,C6) of 50 seconds must be calculated first. Assume the `Second Fortune Co-ordinates' are (GS,CS) and the `Tiny Fortune Co-ordinates' are (U,Z). `t' is the time counting in seconds reckoning in 24-hour system. The `Tiny Fortune' Formula is `U=Z-1+2xGS (Mod 10) & Z=I[6x{{{t (Mod 7200)} (Mod 600)} (Mod 50)}/25]'. No matter male or female, the `Tiny Fortune Co-ordinates' (G7,C7) always spin clockwisely. The `Tiny Fortune Co-ordinates' start to move from the `Origin of Tiny Fortune Co-ordinates' at (UN7,ZN7) to the next Tiny Fortune Co-ordinates' (G7,C7) after four and one-sixth seconds. They oscillate in a loop of 60 and they are expressed as (G7,C7), where `G7' and `C7' are integers. For `G7' values in modulus of ten, 1 is `A', 2 is `B', 3 is `C', 4 is `D', 5 is `E', 6 is `F', 7 is `G', 8 is `H', 9 is `I', 10 is `J'. So, (1,0)=A0, (2,1)=B1, (3,2)=C2, and so on. For `C7' values in modulus of twelve, 0 is `A', 1 is `B', 2 is `C', 3 is `D', 4 is `E', 5 is `F', 6 is `G', 7 is `H', 8 is `I', 9 is `J', 10 is `K', 11 is `L'. So, (1,0)=1A, (2,1)=2B, (3,2)=3C, and so on. For all in terms of alphabets, (1,0)=AA, (2,1)=BB, (3,2)=CC, and so on. They are called `Fortune Codes'. The `Fortune Code' of an interval of four and one-sixth seconds is called the `Tiny Fortune Code' or `Tiny Code'. `I[n]' is an integer function such that it takes the integral part of number `n' without rounding up the number. `U=(Mod 10)' is a special modulated function such that the smallest value of it is 1 and the largest value of it is 10. If U>10 then `U' becomes `U-10' and if U<1 then `U' becomes `U+10'. Thus, the value range of `U=(Mod 10)' is from 1 to 10. `Z=(Mod 7200)' is a modulated function such that if Z>7199 then `Z' becomes `Z-7200' and if Z<0 then `Z' becomes `Z+7200'. Thus, the value range of `Z=(Mod 7200)' is from 0 to 7199. `Z=(Mod 600)' is a modulated function such that if Z>599 then `Z' becomes `Z-600' and if Z<0 then `Z' becomes `Z+600'. Thus, the value range of `Z=(Mod 600)' is from 0 to 599. `Z=(Mod 50)' is a modulated function such that if Z>49 then `Z' becomes `Z-50' and if Z<0 then `Z' becomes `Z+50'. Thus, the value range of `Z=(Mod 50)' is from 0 to 49.

Example

Assume to find the `Tiny Fortune Co-ordinates' (G7,C7) of the time at 3:07:39 a.m. on 15th June of 2011. Firstly, find out the value of `G6' by applying the `Second Fortune' Formula and `G6=4'. Thus, `GS=4'. Next, calculate the value of `t'. t=3x3600+7x60+39. t=11259. Then, apply the `Tiny Fortune' Formula, ` U=Z-1+2xGS (Mod 10) & Z=I[6x{{{t (Mod 7200)} (Mod 600)} (Mod 50)}/25]'. Find the value of `Z' first. Z=I[6x{{{11259 (Mod 7200)} (Mod 600)} (Mod 50)}/25]. Z=I[6x{{11259-7200 (Mod 600)} (Mod 50)}/25]. Z=I[6x{{4059 (Mod 600)} (Mod 50)}/25]. Z=I[6x{4059-600x6 (Mod 50)}/25]. Z=I[6x{459 (Mod 50)}/25]. Z=I[6x{459-50x9}/25]. Z=I[6x9/25]. Z=I[2.16]. Z=2. U=2-1+2x4 (Mod 10). U=9 (Mod 10). U=9. Hence, the `Tiny Fortune Co-ordinates' (G7,C7) of time at 3:07:39 a.m. on 15th June of 2011 is (9,2). The `Tiny Code' is `39', `I2', `9C', `IC' or `YAM-YAN'. If the time is 11:44:42 p.m. on 20th December of 1995, find the `Tiny Fortune Co-ordinates' (G7,C7). Firstly, find out the value of `G6' by applying the `Second Fortune' Formula and `G6=10'. Thus, `GS=10'. Next, calculate the value of `t'. 23x3600+44x60+42. t=85482. Then, apply the `Tiny Fortune' Formula, `U=Z-1+2xGS (Mod 10) & Z=I[6x{{{t (Mod 7200)} (Mod 600)} (Mod 50)}/25]'. Find the value of `Z' first. Z=I[6x{{{85482 (Mod 7200)} (Mod 600)} (Mod 50)}/25]. Z=I[6x{{85482-7200x11 (Mod 600)} (Mod 50)}/25]. Z=I[6x{{6282 (Mod 600)} (Mod 50)}/25]. Z=I[6x{6282-600x10 (Mod 50)}/25]. Z=I[6x{282 (Mod 50)}/25]. Z=I[6x{282-50x5}/25]. Z=I[6x32/25]. Z=I[7.68]. Z=7. U=7-1+2x10 (Mod 10). U=26 (Mod 10). U=26-10x2. U=6. Hence, the `Tiny Fortune Co-ordinates' (G7,C7) of time at 11:44:42 p.m. on 20th December of 1995 is (6,7). The `Tiny Code' is `56', `F7', `6H', `FH' or `GAI-MEI'.

N=01:(1,0)	N=02:(2,1)	N=03:(3,2)	N=04:(4,3)	N=05:(5,4)	N=06:(6,5)	N=07:(7,6)	N=08:(8,7)	N=09:(9,8)	N=10:(10,9)
N=11:(1,10)	N=12:(2,11)	N=13:(3,0)	N=14:(4,1)	N=15:(5,2)	N=16:(6,3)	N=17:(7,4)	N=18:(8,5)	N=19:(9,6)	N=20:(10,7)
N=21:(1,8)	N=22:(2,9)	N=23:(3,10)	N=24:(4,11)	N=25:(5,0)	N=26:(6,1)	N=27:(7,2)	N=28:(8,3)	N=29:(9,4)	N=30:(10,5)
N=31:(1,6)	N=32:(2,7)	N=33:(3,8)	N=34:(4,9)	N=35:(5,10)	N=36:(6,11)	N=37:(7,0)	N=38:(8,1)	N=39:(9,2)	N=40:(10,3)
N=41:(1,4)	N=42:(2,5)	N=43:(3,6)	N=44:(4,7)	N=45:(5,8)	N=46:(6,9)	N=47:(7,10)	N=48:(8,11)	N=49:(9,0)	N=50:(10,1)
N=51:(1,2)	N=52:(2,3)	N=53:(3,4)	N=54:(4,5)	N=55:(5,6)	N=56:(6,7)	N=57:(7,8)	N=58:(8,9)	N=59:(9,10)	N=60:(10,11)